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A hydrogen atom in ground state absorbs ...

A hydrogen atom in ground state absorbs `10.2eV` of energy .The orbital angular momentum of the electron is increases by

A

`1.05 xx 10^(-34) J s`

B

`2.11 xx 10^(-34) J s`

C

`3.16 xx 10^(-34) J s`

D

`4.22 xx 10^(-34) J s`

Text Solution

Verified by Experts

The correct Answer is:
A

`- 13.6 - (-10.2) = - 3.4 eV`.
`(-13.6)/(n^(2)) = - 3.4 or n^(2) = (13.6)/(3.4) = 4`
or `n = 2`
Increase in angular momentum `= (2 h)/(2 pi) = (h)/(2 pi) = (h)/(2 pi)`
`= (6.625 xx 10^(-34))/(2 xx 3.14) J s`
`= 1.05 xx 10^(-34) J s`
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