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In H-atom , a transition takes place fro...

In H-atom , a transition takes place from n=3 to n=2 orbit. Calculate the wavelength of the emitted photon, will the photon be visible ? To which spectral series will this photon belong ( Take `R=1.097xx10^(7)m^(-1))`

A

`6606 Å`

B

`4861 Å`

C

`4340 Å`

D

`4101 Å`

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(lambda) = 1.09 xx 10^(7) [(1)/(2^(2)) - (1)/(3^(2))]`
`implies lambda = 6.606 xx 10^(-7) m implies 6606 Å`
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