A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15eV. What wil be observed by the detector?
(a) 2 photons of energy 10.2 eV
(b) 2 photons of energy 1.4 eV
(c ) One photon of energy 10.2 eV and an electron of energy 1.4 eV
(d) One photon of energy 10.2 eV and another photon of energy 1.4 eV

Options

A. Two proton of energy `10.2 eV`
B. Two proton of energy `1.4 eV`
C. One photon of energy `10.2 eV` and one electron of energy `1.4 eV`
D. One electron having kinetic energy nearly `11.6 eV`.

Answer

D

Explanation

Total energy received by the atom will be `25.2 eV, 13.6 eV` energy is needed to remove the electron from the atteraction of the nucleus. Rest of the energy will be almost available in the from of `KE` of electron