An electron of energy `11.2 eV` undergoes an inelastic collision with a hydrogen atom in its ground state [Neglect recoiling of atom as `m_(H) gt gt m_(e)]`. Then is this case

Options

A. the outgoing electron ha senergy `11.2 eV`
B. the entireenergy is absorbed by the `H` atom and the electron stops
C. `10.2 eV` of the incident electron energy is obsorbed by the `H` atom and the electron would come out with `1.0 eV` energy
D. none of the above

Explanation

To solve the problem step by step, we will analyze the collision of an electron with a hydrogen atom in its ground state.

### Step 1: Understand the energy levels of the hydrogen atom
The energy levels of a hydrogen atom are quantized. The ground state (n=1) has an energy of -13.6 eV, but for our purposes, we are interested in the energy required to excite the atom to higher levels. The first excitation level (n=2) is at -3.4 eV, which means the energy required to move from the ground state to the first excited state is:
\[ E_{n=2} - E_{n=1} = -3.4 \, \text{eV} - (-13.6 \, \text{eV}) = 10.2 \, \text{eV} \]

### Step 2: Analyze the incoming electron's energy
The incoming electron has an energy of 11.2 eV. When it collides with the hydrogen atom, part of this energy can be used to excite the atom.

### Step 3: Determine the energy absorbed by the hydrogen atom
Since the hydrogen atom can absorb a maximum of 10.2 eV to reach the first excited state, we need to see how much energy the electron can transfer to the atom:
- The electron has 11.2 eV of energy.
- The hydrogen atom can absorb 10.2 eV.

Thus, the energy absorbed by the hydrogen atom is 10.2 eV.

### Step 4: Calculate the remaining energy of the electron
After the collision, the remaining energy of the electron can be calculated as:
\[ \text{Remaining energy} = \text{Initial energy} - \text{Energy absorbed} \]
\[ \text{Remaining energy} = 11.2 \, \text{eV} - 10.2 \, \text{eV} = 1.0 \, \text{eV} \]

### Step 5: Conclusion
In conclusion, during the inelastic collision:
- The hydrogen atom absorbs 10.2 eV of energy.
- The electron retains 1.0 eV of energy after the collision.

Thus, the correct statement is that 10.2 eV of the incident electron energy will be absorbed by the hydrogen atom, and the remaining energy of the electron will be 1.0 eV.