The shortest wavelength of the Brackett series of hydrogen like atom (atomic number =Z) is the same as the shortest wavelength of the Blamer series of hydrgeon atom . The value ofn Z is

Options

A. 2
B. 3
C. 4
D. 6

Answer

A

Explanation

Shortest wavelength of Brackett series corresponds to the transition of electron between `n_(1) = 4and n_(1) = oo`. So,
`(Z^(2)) ((13.6)/(16)) = ((13.6)/(4))`
`:. z^(2) = 4`
or `z = 2`