Find the maximum angular speed of the electron of a hydrogen atoms in a statoonary orbit

Options

A. `6.2 xx 10^(15) rad s^(-1)`
B. `4.1 xx 10^(16) rad s^(-1)`
C. `24 xx 10^(10) rad s^(-1)`
D. `9.2 xx 10^(6) rad s^(-1)`

Answer

B

Explanation

Maximim angular speed will be in its ground state. Hence,
`omega_(max) = (v_(1))/(r_(1)) = (2.2 xx 10^(6))/(0.529 xx 10^(-10))`
`= 4.1 xx 10^(16) rad s^(-1)`