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AK(alpha) X-ray emitted from a sample ha...

A`K_(alpha)` X-ray emitted from a sample has an energy of `7.46 ke V. Of which element is the sample made?

A

Calucium `(Ca, Z = 20)`

B

Cobalt `(Co, Z = 27)`

C

Cadmium `(Cd, Z = 48)`

D

Nickel `(Ni, Z = 28)`

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The correct Answer is:
To determine the element from which the K-alpha X-ray is emitted, we can follow these steps: ### Step 1: Understand the K-alpha X-ray Transition K-alpha X-rays are produced when an electron transitions from the n=2 energy level to the n=1 energy level in an atom. The energy of the emitted X-ray can be calculated using the formula: \[ E_{K_{\alpha}} = E_{I} - E_{F} \] where \( E_{I} \) is the energy of the electron in the initial state (n=2) and \( E_{F} \) is the energy of the electron in the final state (n=1). ### Step 2: Calculate the Energies for n=1 and n=2 The energies for the hydrogen-like atom are given by the formula: \[ E_n = -\frac{Z^2 \cdot 13.6 \, \text{eV}}{n^2} \] For \( n=1 \): \[ E_{1} = -\frac{Z^2 \cdot 13.6}{1^2} = -13.6Z^2 \, \text{eV} \] For \( n=2 \): \[ E_{2} = -\frac{Z^2 \cdot 13.6}{2^2} = -\frac{Z^2 \cdot 13.6}{4} = -3.4Z^2 \, \text{eV} \] ### Step 3: Substitute Energies into the K-alpha Energy Formula Now, substituting \( E_{1} \) and \( E_{2} \) into the K-alpha energy equation: \[ E_{K_{\alpha}} = E_{2} - E_{1} \] \[ E_{K_{\alpha}} = (-3.4Z^2) - (-13.6Z^2) \] \[ E_{K_{\alpha}} = 10.2Z^2 \, \text{eV} \] ### Step 4: Convert Given Energy to eV The given energy of the K-alpha X-ray is \( 7.46 \, \text{keV} \). Converting this to electron volts: \[ 7.46 \, \text{keV} = 7.46 \times 10^3 \, \text{eV} \] ### Step 5: Set Up the Equation Now we can set up the equation: \[ 7.46 \times 10^3 = 10.2Z^2 \] ### Step 6: Solve for Z Rearranging the equation to solve for \( Z^2 \): \[ Z^2 = \frac{7.46 \times 10^3}{10.2} \] Calculating this gives: \[ Z^2 \approx 730.39 \] Taking the square root: \[ Z \approx \sqrt{730.39} \approx 27.02 \] ### Step 7: Identify the Element The atomic number \( Z \approx 28 \) corresponds to Nickel (Ni), which is the element from which the K-alpha X-ray is emitted. ### Final Answer The sample is made of Nickel (Ni). ---

To determine the element from which the K-alpha X-ray is emitted, we can follow these steps: ### Step 1: Understand the K-alpha X-ray Transition K-alpha X-rays are produced when an electron transitions from the n=2 energy level to the n=1 energy level in an atom. The energy of the emitted X-ray can be calculated using the formula: \[ E_{K_{\alpha}} = E_{I} - E_{F} \] where \( E_{I} \) is the energy of the electron in the initial state (n=2) and \( E_{F} \) is the energy of the electron in the final state (n=1). ### Step 2: Calculate the Energies for n=1 and n=2 ...
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