Suppose `3.0 xx 10^7` radon atoms are trapped in a basement at a given time. The basement is sealed against further enetry of the gas. The half - life of radon is 3.83 days. How many radon atoms remain after` 31` days?

Explanation

To solve the problem of how many radon atoms remain after 31 days, we will follow these steps:

### Step 1: Identify the given values
- Initial number of radon atoms, \( N_0 = 3.0 \times 10^7 \)
- Half-life of radon, \( t_{1/2} = 3.83 \) days
- Time elapsed, \( t = 31 \) days

### Step 2: Calculate the decay constant (\( \lambda \))
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