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in a neutron induced fission of "".(92...

in a neutron induced fission of `""._(92)u^(235)` nucleus , usable energy of 185 MeV is released if a `""._(92)U^(235)` reactor is continuously openaating it at a power level of 100 MW how long will it take for 1kg of uranium to be consumed in this rector?

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`235` am u of uranium gives `185 MeV `energy. Therefore, the energy given by `1` am u of `._(92)U^(235)` is
`(185)/(2.35) MeV=1(85)/(235) xx1.6 xx10^(-13) J`
But `1` am u `=1.66 xx 10^(-27) kg`. Therefore, energy released by `1.66 xx 10^(-27)kg` of`._(92)U^(235)` is
`(185 xx 1.6 xx 10^(-13)/(235)`
Hence, energy released by `2 kg` of `._(92)U^(235)` ,
`W=(185 xx 1.6 xx10^(-13) xx2)/(235 xx1.66 xx10^(-27)) =1.517 xx 10^(14) J`
Therefore , Therefore , pwer output of reactor `=(W)/(t) =(1.517 xx 10^(14))/((30 days))`
`=(1.517 xx1`0^(14))/(30 xx 24 xx 50 xx 60)`
`=5. 785 xx 10^(7) W`.
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