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Determine the average .^(14)C activity i...

Determine the average `.^(14)C` activity in decays per minute per gram of natural carbon found in living organisms if the concentration of `.^(14)C` relative to that of `.^(12)C` is `1.4 xx10^(-12)` and half -life of `.^(14)C` is `T_(1//2)=57.30` years.

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To determine the average activity of \(^{14}C\) in decays per minute per gram of natural carbon found in living organisms, we will follow these steps: ### Step 1: Calculate the decay constant (\(\lambda\)) The decay constant is given by the formula: \[ \lambda = \frac{\ln(2)}{T_{1/2}} \] where \(T_{1/2} = 57.30\) years. First, we need to convert the half-life into minutes: ...
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(a) Determine the number of carbon ._6^(14)C atoms present for every gram of carbon ._6^(12)C in a living organism. Find (b) The decay constatnt and (c ) the activity of this sample.

A piece of wood form the ruins of an ancient building was found to have a C^(14) activity of 12 disintegrations per minute per gram of its carbon content. The C^(14) activity of the living wood is 16 disintegrations/minute/gram. How long ago did the trees, from which the wooden sample came, die? Given half-life of C^(14) is 5760 years.

Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . A nuclear explosion has taken place leading to an increase in the concentration of C^(14) in nearby areas. C^(14) concentration is C_(1) in nearby areas and C_(2) in areas far away. If the age of the fossil is determined to be T_(1) and T_(2) at the places , respectively, then

Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . What should be the age of fossil for meaningful determination of its age ?

The half - life of ._6C^(14) , if its lamda is 2.31 xx10^(-4) " year"^(-1) is

The ratio of C^(14)//C^(12) in dead tissue is less than that in fresh tissue.

A bone containing 200 g carbon-14 has beta -decay rate of 375 decay/min. Calculate the time that has elapsed since the death of the living one. Given the rate of decay for the living organism is equal to 15 decay per min per gram of carbon and half-life of carbon-14 is 5730 years.

A bone containing 200 g carbon-14 has beta -decay rate of 375 decay/min. Calculate the time that has elapsed since the death of the living one. Given the rate of decay for the living organism is equal to 15 decay per min per gram of carbon and half-life of carbon-14 is 5730 years .

CENGAGE PHYSICS ENGLISH-NUCLEAR PHYSICS-Exercise 5.2
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  2. A radioactive sample has a mass m, decay cosntant lambda, and molecul...

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  3. Calculate the time taken to decay 100 percent of a radioactive sample...

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  4. The activity of a sample of radioactive material is R(1) at time t(1)a...

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  5. A .(92)^(238)U undergoes alpha decay. What is the resulting daughter n...

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  6. Is the sulphur isotope .(16)^(38)S likely to be stable?

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  7. Determine the average .^(14)C activity in decays per minute per gram o...

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  8. Radium 226 is found to have a decay constant of 1.36 xx10^(-11) Bq. ...

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  9. A bottle of red wine is thought to have been sealed about 5 years ago....

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  10. A radio nuclide A(1) with decay constant lambda(1) transforms into a r...

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  11. Consider the beta decay of an unstable .(6)^(14)C nuleus initially at ...

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  12. The atomic mass of uranium .(92)^(238)U is 238.0508 u, that of throium...

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  13. Refer to illustration 5.10, the energy released by the alpha - decay o...

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  14. Estimate the minimum amount of .(235)^(92)U that needs to undergo fiss...

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  15. The isotope .6^(14)C is radioactive and has a half-life of 5730 years ...

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  16. The half-life of the radioactive nucleus .(86)^(226)Ra is 1.6 xx10^(3)...

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  17. Radon, .(86)^(222)Rn, is a radioactive gas that can be trapped in the ...

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  18. The .(88)^(226)Ra nucleus undergoes alpha-decay to .(86)^(222)Rn. Calc...

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  19. Calculate the energy released when three alpha particles combine to fo...

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  20. (a) Find the energy needed to remove a neutron from the nucleus of the...

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