Consider the beta decay of an unstable `._(6)^(14)C` nuleus initially at rest: `._(6)^(14)C rarr ._(7)^(14)N +._(-1)^(0)e +v._(e)`.
Is it possible for the maximum kinetic energy of the emiited beta particle to be exactly equal to `Q`?

Explanation

To determine whether the maximum kinetic energy of the emitted beta particle can be exactly equal to the Q value in the beta decay of \( _{6}^{14}C \), we need to analyze the conservation of energy and momentum during the decay process.

### Step-by-Step Solution:

1. **Understanding the Decay Process:**
The beta decay of \( _{6}^{14}C \) can be represented as:
\[
_{6}^{14}C \rightarrow _{7}^{14}N + e^{-} + \bar{\nu}_{e}
...