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A radioactive element P disintegrates in...

A radioactive element P disintegrates into Q which further disintegrates into R as shown in figure.

At t=0, number of nuclei of P, Q and R are `N_(0)` 0 and 0. At time t number of nuclei of P,Q and R are `N_(1) , N_(2)` and `N_(3)` respectively . The ratio of `N_(1)` to `N_(2)` maximum is K Find the value of K.

A

at no time this is possible

B

``2

C

`1//2`

D

`(ln2)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
b
`(dN_(2))/(dt)=lambda N_(1) -2 lambda N_(2)`
For `n_(2)` to be maximum,
`(dN_(2))/(dt)=0`
`rArr lambda N_(1)= 2 lambda N_(2)` or `(N_(1))/(N_(2)) =2`.
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