If the` Q` value of an endothermic reaction is `11.32 MeV`, then the minimum energy of the reactant nuclei to carry out the reaction is (in laboratotry frame of reference)

Options

A. `11.32 MeV`
B. less than `11.32 MeV`
C. greater than `11.32 MeV`
D. Data is insufficeint

Explanation

To solve the problem, we need to determine the minimum energy of the reactant nuclei required for an endothermic reaction given that the Q value is 11.32 MeV.

### Step-by-Step Solution:

1. **Understanding the Q Value**:
The Q value of a nuclear reaction indicates the energy released or absorbed during the reaction. For an endothermic reaction, the Q value is positive, meaning energy is absorbed.

2. **Kinetic Energy Requirement**:
In an endothermic reaction, the kinetic energy of the reactant nuclei must be greater than the Q value for the reaction to occur. This is because the reactants need to provide enough energy to overcome the energy barrier represented by the Q value.

3. **Formula for Minimum Kinetic Energy**:
The minimum kinetic energy (K.E.) required for the reactants can be expressed as:
\[ K.E._{\text{min}} = Q + \text{(additional energy)} \]
However, for the purpose of this problem, we can simplify our approach by stating that:
\[ K.E._{\text{min}} > Q \]
This means that the minimum kinetic energy must be greater than the Q value.

4. **Substituting the Q Value**:
Given that the Q value is 11.32 MeV, we can write:
\[ K.E._{\text{min}} > 11.32 \text{ MeV} \]

5. **Conclusion**:
Therefore, the minimum energy of the reactant nuclei to carry out the reaction must be greater than 11.32 MeV.

### Final Answer:
The minimum energy of the reactant nuclei to carry out the reaction is greater than 11.32 MeV.