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A radioactive substance X decays into an...

A radioactive substance X decays into another radioactive substance Y Initially only X was present. `lambda_(x)` and `lambday_(y)` are the disnttegration constants of Xa nd Y `N_(x)` and `N_(y)` are the number of nuclie of X and Y at any time t. Number of nuclei `N_(y)` will be maximum when

A

`(N_(y))/(N_(x) -N_(y)=lambda_(y)/lambda_(x)-lambda_(y))`

B

`(N_(y))/(N_(x) -N_(y)=lambda_(y)/lambda_(x)-lambda_(y))`

C

`lambda_(y) N_(y)=lambda_(x)N_(x)`

D

`lambda_(y) N_(x)=lambda_(x)N_(y)`

Text Solution

Verified by Experts

The correct Answer is:
c

`Net rate foramtion of `Y` at any time `t` is
`(dN_(y))/(dt) =lamb_(y) N_(y)`da_(x) N_(x)-lambda`
`N_(y)` is maximum when
`(dN_(y))/(dt) =0`
or `lambda_(x) N_(x)-lambda_(y) N_(y)`.
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