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A rodiactive nucleus is being produced a...

A rodiactive nucleus is being produced at a constant rate `alpha` per second Its decay constant is `lambda` If `N_(0)` are the number of nuclie at tieme t=O then, maximum number of nuclei possible are

A

`(alpha)/(lambda)`

B

`(N_(0) alpha)/(lambda)`

C

`N_(0)`

D

`(lambda)/(alpha+N_(0))`

Text Solution

Verified by Experts

The correct Answer is:
a
Maximum number of nuclei will be present when rate of decay =rate of formation
or `lambda N=alpha`
`:. N=(alpha)/(lambda)` .
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