The ratio of molecules mass of two radiactive substances is `(3)/(2)` and the ratio of their decay constant is `(4)/(3)` Then the ratio of their intial activity per mol will be

Options

A. `2`
B. `(8)/(9)`
C. `(4)/(3)`
D. `(9)/(8)`

Answer

c

Explanation

Activity, `R=lambdaN`. Number of nuclei `N` per mole are equal for both the substance.
`:. R prop lambda`
or `(R_(1))/(R_(2)) =(lambda_(1))/(lambda_(2)) =(4)/(3)`.