N(1) atoms of a radioactive element emit...

`N_(1)` atoms of a radioactive element emit `N_(2)` "beta" particles per second The decay constant of the element is (in` s^(-1))`

`(N_(1))/(N_(2))`

`(N_(2))/(N_(1))`

`N_(1) ln(2)`

`N_(2) ln(2)`

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The correct Answer is:

Activity of a radioactive substance,
`R =lambda N`
`:. Lambda =(R)/(N)`
Here, `R=N_(2)` particles per second and `N=N_(1)`.
`:. Lambda=(N_(2))/(N_(1))`.

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