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Binding energy per nucleon of 1^(H^(2)) ...

Binding energy per nucleon of `1^(H^(2))` and `2^(He^(2))` are 1.1 MeV and `7.0` respectively Energy realsed in the process `1^(H^(2))+1^(He^(4))` is

A

20.8 MeV

B

16.6MeV

C

25.2MeV

D

23.6MeV

Text Solution

Verified by Experts

The correct Answer is:
d
Energy released would be
`Delta E` =total energy of `._(2)He^(4)`
`- 2xx` (total binding energy of `._(1)_(He)^(4)`
` 4 xx 7.0 -2(1.1)(2)`
`=23.6 MeV` .
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