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A radioactive nucleus undergoes a series...

A radioactive nucleus undergoes a series of deacy according to the scheme.
`Aoverset(alpha)rarrA_(1)overset(beta^(-))rarrA_(2)overset(alpha)rarrA_(3)overset(gamma)rarrA_(4)`
If the mass number and atomic number of `A` are `180` and `72` respectively, what are these numbers for `A_(4)`.

A

`172 and 69`

B

`174 and 70`

C

`176 and 69`

D

`176 and 70`

Text Solution

Verified by Experts

The correct Answer is:
a
Two `alpha`-particles reduce mass number by `8 `.
Therefore, new mass number `=180 -8=172`
Emission of two `alpha`-particles reduces charge number by `4`.
Emission of `beta`-particles increases charge number by `1`.
Therefore the new charge number `=72-4+1=69`.
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