If mass of `U^(235)=235.12142 a.m.u.`, mass of `U^(236) =236.1205 amu`, and mass of neutron `=1.008665 am u`, then the energy required to remove one neutron from the nucleus of `U^(236)` is nearly about.

Options

A. `75 MeV`
B. `6.5 MeV`
C. `1 eV`
D. zero

Explanation

To find the energy required to remove one neutron from the nucleus of Uranium-236, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Masses:**
- Mass of Uranium-236 (U-236) = 236.1205 amu
- Mass of Uranium-235 (U-235) = 235.12142 amu
- Mass of neutron = 1.008665 amu

2. **Write the Reaction:**
The reaction for removing one neutron from U-236 can be represented as:
\[ \text{U-236} \rightarrow \text{U-235} + \text{n} \]
where n is the neutron.

3. **Calculate the Mass Defect (Δm):**
The mass defect is calculated as:
\[ \Delta m = \text{mass of reactants} - \text{mass of products} \]
Here, the mass of reactants is the mass of U-236, and the mass of products is the sum of the masses of U-235 and the neutron:
\[ \Delta m = \text{mass of U-236} - (\text{mass of U-235} + \text{mass of neutron}) \]
Substituting the values:
\[ \Delta m = 236.1205 \, \text{amu} - (235.12142 \, \text{amu} + 1.008665 \, \text{amu}) \]
\[ \Delta m = 236.1205 \, \text{amu} - 236.130085 \, \text{amu} \]
\[ \Delta m = -0.009585 \, \text{amu} \]

4. **Convert Mass Defect to Energy:**
The energy equivalent of the mass defect can be calculated using Einstein's equation \(E = \Delta m c^2\). However, in nuclear physics, we often use the conversion factor:
\[ 1 \, \text{amu} \approx 931.5 \, \text{MeV} \]
Therefore, the energy required (E) is:
\[ E = \Delta m \times 931.5 \, \text{MeV} \]
Substituting the value of Δm:
\[ E = -0.009585 \, \text{amu} \times 931.5 \, \text{MeV/amu} \]
\[ E \approx -8.93 \, \text{MeV} \]

5. **Interpret the Result:**
Since we are looking for the energy required to remove the neutron, we take the absolute value:
\[ E \approx 8.93 \, \text{MeV} \]

### Final Answer:
The energy required to remove one neutron from the nucleus of Uranium-236 is approximately **8.93 MeV**.