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The compound unstabel nucleus .(92)^(236...

The compound unstabel nucleus `._(92)^(236)U` often decays in accordance with the following reaction
`._(92)^(236)U rarr ._(54)^(140)Xe +._(38)^(94)Sr ` + other particles
During the reaction, the uranium nucleus ''fissions'' (splits) into the two smaller nuceli have higher nuclear binding energy per nucleon (although the lighter nuclei have lower total nuclear binding energies, because they contain fewer nucleons).
Inside a nucleus, the nucleons (protonsa and neutrons)attract each other with a ''strong nuclear'' force. All neutrons exert approxiamtely the same strong nuclear force on each other. This force holds the nuclear are very close together at intranuclear distances.
A proton and a neutron are both shot at `100 m s^(-1)` toward a `._6^(12)C` nucleus. Which particle, if either, is more likely to be absorbed by the nucleus?

A

The proton

B

The neutron

C

Both particles are about equally likely to be absorbed,.

D

Neither particle will be absorbed.

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The correct Answer is:
To determine which particle, if either, is more likely to be absorbed by the carbon-12 nucleus when a proton and a neutron are shot at it with a speed of 100 m/s, we can analyze the interactions based on the properties of protons and neutrons. ### Step-by-Step Solution: 1. **Understanding the Nucleus**: - The carbon-12 nucleus consists of 6 protons and 6 neutrons. Protons are positively charged, while neutrons are neutral. 2. **Behavior of the Neutron**: - When a neutron approaches the carbon nucleus, it does not experience any electrostatic repulsion because it is neutral. - As the neutron gets closer to the nucleus, it will be attracted by the strong nuclear force, which is a force that acts between nucleons (protons and neutrons) at very short distances. - Therefore, the neutron is likely to be absorbed by the nucleus. 3. **Behavior of the Proton**: - When a proton approaches the carbon nucleus, it will face electrostatic repulsion from the 6 positively charged protons already present in the nucleus. - This electrostatic force of repulsion is significant and will counteract the attractive strong nuclear force that acts on the proton. - As a result, the proton is less likely to be absorbed by the nucleus due to this repulsion. 4. **Conclusion**: - Since the neutron is attracted by the strong nuclear force and faces no repulsion, while the proton is repelled by the existing protons, the neutron is more likely to be absorbed by the carbon-12 nucleus. ### Final Answer: The neutron is more likely to be absorbed by the nucleus.

To determine which particle, if either, is more likely to be absorbed by the carbon-12 nucleus when a proton and a neutron are shot at it with a speed of 100 m/s, we can analyze the interactions based on the properties of protons and neutrons. ### Step-by-Step Solution: 1. **Understanding the Nucleus**: - The carbon-12 nucleus consists of 6 protons and 6 neutrons. Protons are positively charged, while neutrons are neutral. 2. **Behavior of the Neutron**: ...
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The compound unstabel nucleus ._(92)^(236)U often decays in accordance with the following reaction ._(92)^(236)U rarr ._(54)^(140)Xe +._(38)^(94)Sr + other particles During the reaction, the uranium nucleus ''fissions'' (splits) into the two smaller nuceli have higher nuclear binding energy per nucleon (although the lighter nuclei have lower total nuclear binding energies, because they contain fewer nucleons). Inside a nucleus, the nucleons (protons and neutrons)attract each other with a ''strong nuclear'' force. All neutrons exert approxiamtely the same strong nuclear force on each other. This force holds the nuclear are very close together at intranuclear distances. Why is a ._2^4He nucleus more stable than a ._3^4Li nucleus?

The compound unstabel nucleus ._(92)^(236)U often decays in accordance with the following reaction _(92)^(236)U rarr ._(54)^(140)Xe +_(38)^(94)Sr+ other particles During the reaction, the uranium nucleus ''fissions'' (splits) into the two smaller nuceli have higher nuclear binding energy per nucleon (although the lighter nuclei have lower total nuclear binding energies, because they contain fewer nucleons). Inside a nucleus, the nucleons (protonsa and neutrons)attract each other with a ''strong nuclear'' force. All neutrons exert approxiamtely the same strong nuclear force on each other. This force holds the nuclear are very close together at intranuclear distances. In the nuclear reaction presented above, the ''other particles'' might be .

The compound unstabel nucleus ._(92)^(236)U often decays in accordance with the following reaction ._(92)^(236)U rarr ._(54)^(140)Xe +._(38)^(94)Sr + other particles During the reaction, the uranium nucleus ''fissions'' (splits) into the two smaller nuceli have higher nuclear binding energy per nucleon (although the lighter nuclei have lower total nuclear binding energies, because they contain fewer nucleons). Inside a nucleus, the nucleons (protonsa and neutrons)attract each other with a ''strong nuclear'' force. All neutrons exert approxiamtely the same strong nuclear force on each other. This force holds the nuclear are very close together at intranuclear distances. Which of the following graphs might represent the relationship between atomic number (i.e., ''atomic weight'') and the total binding energy of the nucleus, for nuclei heavier than ._(38)^(94)Sr ?

The value of binding energy per nucleon is

The binding energy per nucleon is maximum in the case of.

The binding energy per nucleon is maximum in the case of.

Average binding energy per nucleon over a wide range is

When the number of nucleons in a nuclues increases the binding energy per nucleon

As the mass number A increases, the binding energy per nucleon in a nucleus.

When two nuclei (with A=8) join to form a heavier nucleus , the binding energy (B.E) per nucleon of the heavier nuclei is

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