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Staements I: .zX^4 undergoes 2 alpha-dec...

Staements I: `._zX^4` undergoes `2 alpha`-decays, `2 beta`-decays (negative `beta`) and `2 gamma`-decays. As a result, the daughter product is `_(z-2)X^(A-8)`.
Staements II: In `beta`-decay, the mass number decreases by 4 unit and atomic number decreases by `2` unit. In `beta`-decay (negative `beta`), the mass number remains unchanged and atomic number increases by `1` unit. In `gamma`-decay, mass number and atomic number remain unchanged.

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To solve the problem, we will analyze the given statements step by step. ### Step 1: Understanding the initial state We start with a nucleus represented as \( _ZX^A \), where \( Z \) is the atomic number and \( A \) is the mass number. ### Step 2: Alpha Decay In alpha decay, the nucleus emits an alpha particle, which consists of 2 protons and 2 neutrons. This results in: - The atomic number \( Z \) decreases by 2. - The mass number \( A \) decreases by 4. After the first alpha decay: - New atomic number: \( Z - 2 \) - New mass number: \( A - 4 \) After the second alpha decay: - New atomic number: \( Z - 4 \) - New mass number: \( A - 8 \) ### Step 3: Beta Decay In beta decay (specifically negative beta decay), a neutron is converted into a proton, which results in: - The atomic number \( Z \) increases by 1. - The mass number \( A \) remains unchanged. After the first beta decay: - New atomic number: \( Z - 4 + 1 = Z - 3 \) - Mass number remains: \( A - 8 \) After the second beta decay: - New atomic number: \( Z - 3 + 1 = Z - 2 \) - Mass number remains: \( A - 8 \) ### Step 4: Gamma Decay Gamma decay involves the emission of gamma radiation, which does not change the atomic number or mass number. Thus, after two gamma decays: - Atomic number remains: \( Z - 2 \) - Mass number remains: \( A - 8 \) ### Step 5: Final Result After all the decays, the final daughter product is: - Atomic number: \( Z - 2 \) - Mass number: \( A - 8 \) This confirms that Statement I is true. ### Step 6: Analyzing Statement II Now let's check Statement II: 1. In alpha decay, the mass number decreases by 4 units and atomic number decreases by 2 units. **(True)** 2. In beta decay, the mass number remains unchanged and atomic number increases by 1 unit. **(True)** 3. In gamma decay, mass number and atomic number remain unchanged. **(True)** Since all parts of Statement II are correct, we conclude that Statement II is also true. ### Conclusion Both Statement I and Statement II are true, and Statement II correctly explains Statement I.

To solve the problem, we will analyze the given statements step by step. ### Step 1: Understanding the initial state We start with a nucleus represented as \( _ZX^A \), where \( Z \) is the atomic number and \( A \) is the mass number. ### Step 2: Alpha Decay In alpha decay, the nucleus emits an alpha particle, which consists of 2 protons and 2 neutrons. This results in: - The atomic number \( Z \) decreases by 2. ...
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Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z._-2X^(A-B) . Staements II: In alpha -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z._-2X^(A-B) . Staements II: In alpha -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

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