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How many alpha and beta particles are em...

How many alpha and beta particles are emitted when uranium `(._(92)U^(238))` decays to lead `(._(82)Pb^(206))`?

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`._(92)^(238)U rarr. _(82)^(206)Pb + x ._2^4He +y. _(-1)^(0)e`
First, we find the number of `alpha`-particles. The change in mass number during the decay from uranium to lead is `238-206=32`. Therefore, the number of `alpha`-particels (with mass `"no". 4`) is `32//4=8`.
The change in atomic number (i.e., number of protons) taking place when `8 alpha`-particles are emitted and lead is formed `=92-(82+16)=6` which means six `beta`-particles are emitted.
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