A stream of protons and deuterons in a vacuum chamber enters a uniform magnetic field. Both protons and deuterons have been subjected to same accelerating potential, hence the kinetic energies of the particles are the same. If the ion-stream is perpendicular to the magnetic field and the protons move in a circular path of radius 15 cm, find the radius of the path traversed by the deuterons. Given that mass of deuteron is twice that of a proton.

Explanation

To solve the problem, we need to find the radius of the path traversed by the deuterons (Rd) when they are subjected to the same accelerating potential as the protons (Rp) and are moving in a uniform magnetic field.

### Step-by-Step Solution:

1. **Understanding the Given Information**:
- The radius of the circular path of protons (Rp) = 15 cm = 0.15 m.
- The mass of a deuteron (Md) is twice that of a proton (Mp), i.e., Md = 2Mp.
- The kinetic energies of protons and deuterons are equal since they are subjected to the same accelerating potential.
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