Home
Class 12
PHYSICS
A particle of mass m and charge q is pr...

A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation fo the particle as it comes out of the magnetic field if the width d of the regions is very smaller then

Text Solution

Verified by Experts

The radius of the circular orbit
is `r=(mv)/(qB)`
The deviation `theta` may be obtained
from in as
`sin theta =d/r=(dBq)/(mv)`
or ` theta =sin^-1((dBq)/(mv))`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Solved Example|25 Videos
  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 1.1|22 Videos
  • INDUCTANCE

    CENGAGE PHYSICS ENGLISH|Exercise Concept Based|8 Videos
  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise True and False|3 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation of the particle as it comes out of the magnetic field if ihe width d of the region is (2mv)/(qB)

A particle of mass m and charge q is projected into a region having a perpendicular magnetic, field B . Find the angle of deviation of the particle as it comes out of the magnetic field if the, width of the region is b , which is very slightly less than (mv)/(2Bq)

A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B . The time takeen by the particle to complete one revolution is

A particle of mass m and charge q is thrown in a region where uniform gravitational field and electric field are present. The path of particle:

A charged particle (q, m) enters perpendicular in a uniform magnetic field B and comes out field as shown. Find the angle of deviation theta for particle to cross magnetic field will be

A charged particle of mass m and charge q is projected into a uniform magnetic field of induciton vecB with speed v which is perpendicular to vecB . The width of the magnetic field is d. The impulse imparted to the particle by the field is (dlt lt mv//qB)

If a charged particle goes unaccelerated in a region containing electric and magnetic fields,

If a charged particle goes unaccelerated in a region containing electric and magnetic fields,

A charged particle moves in a uniform magnetic field. The velocity of the particle at some instant makes an acute angle with the magnetic field. The path of the particle will be

The figure shows two regions of uniform magnetic field of strengths 2B and 2B. A charged particle of mass m and charge q enters the region of the magnetic field with a velocity upsilon = (q B w)/(m) , where w is the width of each region of the magnetic field. The time taken by the particle to come out of the region of the magnetic field is