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An electron accelerated by a potential d...

An electron accelerated by a potential difference `V=1.0 kV` moves in a uniform magnetic field at an angle `alpha = 30^@` to the vector B whose modulus is `B=29 mT.` Find the pitch of the helical trajectory of the electron.

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To find the pitch of the helical trajectory of the electron, we can follow these steps: ### Step 1: Determine the velocity of the electron The kinetic energy gained by the electron when it is accelerated through a potential difference \( V \) is given by: \[ KE = Q \cdot V \] where \( Q \) is the charge of the electron and \( V = 1.0 \, \text{kV} = 1000 \, \text{V} \). ...
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