An electron accelerated by a potential difference `V= 3` volt first enters into a uniform electric field of a parallel plate capacitor whose plates extend over a length `l= 6 cm` in the direction of initial velocity. The electric field is normal to the direction of initial velocity and its strength varies with time as `E= alpha t,` where `alpha= 3600 V m^-1 s^-1.` Then the electron enters into a uniform magnetic field of induction `B = pi xx 10^-9 T.` Direction of magnetic field is same as that of the electric field. Calculate pitch of helical path traced by the electron in the magnetic field. (Mass of electron, `m = 9 xx 10^-31 kg`)

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Calculate the initial velocity of the electron after being accelerated by the potential difference.
The kinetic energy gained by the electron when accelerated through a potential difference \( V \) is given by:
\[ \frac{1}{2} m u^2 = eV \]
Where:
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