The horizontal component of the earth's magnetic field at a certain place is `3 xx 10^-5 T` and the direction of the field is from the geographic south to the geographic north. A very long straight conductor is carrying a steady current of 1 A. What is the force per unit length on it when it is placed on a horizontal table and the direction of the current is
(a) east to west,
(b) south to north?

Explanation

To solve the problem, we will use the formula for the magnetic force per unit length on a current-carrying conductor in a magnetic field. The formula is given by:

\[ F/L = I \cdot B \cdot \sin(\theta) \]

where:
- \( F/L \) is the force per unit length,
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