Home
Class 12
PHYSICS
The cube as shown in Fig. 1.61, 75.0 cm ...

The cube as shown in Fig. 1.61, 75.0 cm on a side, is placed in a uniform magnetic field of 0.860 T parallel to the x-axis. The wire abcdef carries a current of 6.58 A in the direction indicated.
(a) Determine the magnitude and direction of the force acting on the segment ab.
(b) Determine the magnitude and direction of the force acting on the sement bc.
(c) Determine the magnitude and direction of the force acting on the segment cd.
(d) Determine the magnitude and direction of the force acting on the segment de.
(e) Determine the magnitude and direction of the force acting on the segment ef.
(f) What are the magnitude and direction of the total force on the wire ?

Text Solution

Verified by Experts

(a) `vecF=Ivecl_(ab)xxvecB=I(l_(ab)B)hatjxxhati`
`=-(6.58A)(0.750m)(0.860m)hatk`
`=(-4.24N)hatk`
(b) `vecF=Ivecl_(bc)xxvecB=I(l_(bc)B)[(hati-hatk)/(sqrt2)xxhati]`
`=(6.58A)(0.750m)(0.860T)hatj`
`=(-4.24N)hatj`
(c) `vecF=Ivecl_(cd)xxvecB=I(l_(cd)B)[(hatk-hatj)/(sqrt2)xxhati]`
`=(6.58A)(0.750m)(0.860T)[hatj+hatk]`
`implies vecF=(4.24N)[hatj+hatk]`
(d) `vecF=Ivecl_(de)xxvecB=I(l_(de)B)[(-hatkxxhati)`
`=-(6.58A)(0.750m)(0.860T)hatj`
`=(4.24N)hatj`
(e) `vecF=Ivecl_(ef)xxvecB=I(l_(ef)B)(-hati)xxhati=0`
(f) Summing all the forces in parts (a)-(c), we have
`F_("total")=(-4.24N)hatj`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Exercise1.3|14 Videos

  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Exercises Subjective|10 Videos

  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 1.1|22 Videos

  • INDUCTANCE

    CENGAGE PHYSICS ENGLISH|Exercise Concept Based|8 Videos

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise True and False|3 Videos

Similar Questions

Explore conceptually related problems

The magnitude and direction of magnetic force on the side AC in the given figure will be

A circular loop of radius R=20 cm is placed in a uniform magnetic field B=2T in xy -plane as shown in figure. The loop carries a current i=1.0 A in the direction shown in figure. Find the magnitude of torque acting on the loop.

A circular loop of radius R=20 cm is placed in a uniform magnetic field B=2T in xy -plane as shown in figure. The loop carries a current i=1.0 A in the direction shown in figure. Find the magnitude of torque acting on the loop.

Find the magnitude and direction of magnetic field at point P due to the current carrying wire as shown in

Resultant force acting on a diamagentic material in a magnetic field is in direction

A square of side 2.0 m is placed in a uniform magnetic field B=2.0 T in a direction perpendicular to the plane of the square inwards. Equal current i=3.0 A is flowing in the directions shown in figure. Find the magnitude of magnetic force on the loop.

A square of side 2.0 m is placed in a uniform magnetic field B=2.0 T in a direction perpendicular to the plane of the square inwards. Equal current i=3.0 A is flowing in the directions shown in figure. Find the magnitude of magnetic force on the loop.

Assertion: In projectile motion, the acceleration is constant in both magnitude and direction but the velocity changes in both magnitude and direction. Reason: When a force or accelration is acting in an oblique direction to the direction of velocity then both magnitude and direction of the velocity may be changed.

A current carrying circular loop of radius R is placed in a uniform magnetic field B_(0) Tesla in x-y plane as shown in figure. The loop carries a current i = 1A in the direction shown. Find the torqure acting on the loop

Find the magnitude and direction of force on following current carrying wires. Direction of magnetic field is indicated in each case.