A particle of charge q and mass m moves in a circular orbit of radius r with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

Options

A. `omega and q`
B. `omega,q and m`
C. `q and m`
D. `omega and m`

Answer

c

Explanation

The angular momentum L of the particle is given by `L=mr^2omega`
`to` where `omega=2pin`
`:.` Frequency `n=omega/(2pi)`
Further `ip=qxxn=(omegaq)/(2pi)`
Magnetic moment, `M=iA=(omegaA)/(2pi)xxpir^2`
`:. M=(omegaqr^2)/2 implies M/L=(omegaqr^2)/(2mr^2omega)=q/(2m)`.