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In the figure shown a charge `q` moving with a velocity v along the x-axis enter into a region of uniform magnetic field. The minimum value `v` so that the charge `q` is able to enter the region `xgtb`

A

`(qbB)/m`

B

`(q(b-a)B)/m`

C

`(qaB)/m`

D

`(q(b+a)B)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
b
Width of the magnetic field region (b-a)`leR`, where 'R' is
its radius of curvature inside magnetic field.
`:. R=(mv)/(qB) =(b-a) implies v_(min)=((b-a)qB)/m`
(b ) is the correct option.
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