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A rod of length l is placed perpendicula...

A rod of length `l` is placed perpendicular to a long wire carrying current `i`. The rod is moved parallel to the wire with a velocity `v`. Find the emf induced in the rod, if its nearest end is at a distance a from the wire.

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Consider a segment of rod of length `dx`, at a distance `x` from the wire, emf induced in the segment, ltbr. `depsilon = (mu_(0)i)/(2pix)dxv`
`:.` `epsilon = int_(a)^(a + l)(mu_(0)ivdx)/(2pix) = (mu_(0)iv)/(2pi)1n((l + a)/(a))`
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CENGAGE PHYSICS ENGLISH-ELECTROMAGNETIC INDUCTION-Exercise 3.2
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