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Shows rod PQ of mass m and resistance r ...

Shows rod `PQ` of mass `m` and resistance `r` moving on two fixed, resistanceless, smooth conducting rails (closed on both sides by resistances `R_(1) and R_(2)`). Find the current in the rod (at the instant its velocity is `v`).

Text Solution

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The given circuit is equivalent to the following diagram:

`I =(Blv)/(r +(R_(1)R_(2))/(R_(1) + R_(2))`
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CENGAGE PHYSICS ENGLISH-ELECTROMAGNETIC INDUCTION-Exercise 3.2
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  4. A rod of length l is placed perpendicular to a long wire carrying curr...

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  5. A rectangular loop is moving parallel to a long wire carrying current ...

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  7. Rod PQ of length 2l is rotating about its midpoint C in a uniform magn...

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  8. A rod of length L and resistance r rotates about one end as shown in ....

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  10. A rod of length l is rotating with an angular speed omega about one of...

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  11. A rod of length l is rotating with an angular speed omega about one of...

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  12. Shows rod PQ of mass m and resistance r moving on two fixed, resistanc...

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  13. A rod PQ of length l is rotating about end P, with an angular velocity...

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  14. A ring rotates with angular velocity omega about an axis perpendicula ...

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  15. A ring rotates with angular velocity omega about an axis in the plane ...

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  16. A rod AB moves with a uniform velocity v in a uniform magnetic field ...

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  17. The cube shown in, 50.0 cm on a side, is in a uniform magnetic field o...

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  18. A rod of mass m, length l and resistance R is sliding down on a smooth...

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  19. A conducting rod AC of length 4l is rotated about a point O in a unifo...

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  20. Consider the sliding wire circuit shown in . The wire slides at const...

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