A rod AB moves with a uniform velocity v in a uniform magnetic field as shown in figure
(##HCV_VOL2_C38_E01_033_Q01##)

Explanation

(a) `epsilon = vBL = (5.00m//s)(0.450 T)(0.300m) = 0.675 V`.
(b) The potential difference between the ends of the rod is just the motional emf
( c) The positive charges are moved to end `b`, so `b` is at a higher potential.
(d) `E = (V)/(L) = 0.675 V/(0.300m) = 2.25m^(-1)`.
`b`.