Consider the sliding wire circuit shown in . The wire slides at constant speed and the plane of the circuit is perpendicular to a uniform magnetic field. Show that the induced emf is given by `E = Blv^(2)t//D` foe `0 lt t lt D//v` What is the expression for the emf for `t gt D//v`?

Explanation

`E_(induced) = Bvl`
where `B, v, l` are perpendicular to each other.
`l = 2x tan alpha`
`x = vt`
`rarr` `E_(induced) = bv^(2)(vt)tan alpha`
`= 2bv^(2)(tan alpha)t`
For `t gt (D)/(v)`, the length involved is `l`
`:.` `E_(ind) = Bvl`