Home
Class 12
PHYSICS
In an LR circuit as shows in Fig.when th...

In an `LR` circuit as shows in Fig.when the swtich is closed, how much time will it take for the current to grow to a value `n` times the maximum value of current (where `n lt 1)`?

Text Solution

Verified by Experts

We know that `I = (epsilon)/(R ) (1 - e^(-t//tau))`
`I = n(epsilon)/(R )` (given)
`n = (epsilon)/(R ) = (epsilon)/(R ) (1 - e^(-t//tau))`
or `e^(-t//tau) = 1 -n`
or `t = tau` In `((1)/(1 - n))`
Promotional Banner

Topper's Solved these Questions

  • INDUCTANCE

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|3 Videos
  • INDUCTANCE

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.1|24 Videos
  • HEATING EFFECT OF CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Thermal Power in Resistance Connected in Circuit|27 Videos
  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct Answer type|2 Videos

Similar Questions

Explore conceptually related problems

In the circuit shown in fig. when the switch is closed, the capacitor charges with a time constant

In the circuit shown in figure switch S is closed at time t=0 Current I from the battery at time t is given by

In the circuit shown, switch S is closed at time t = 0 . Find the current through the inductor as a function of time t .

In the circuit shown if Fig. the switch S is closed at time t = 0. The current through the capacitor and inductor will be equal at time t equal (given R = sqrt(L//C)

Find the time after which current in the circuit becomes 80% of its maximum value

In the circuit shwon in fig. the current I has a value equal to

In the circuit shwon in fig. switch S is closed at time t = 0. Let I_1 and I_2 be the currents at any finite time t, then the ratio I_1// I_2

In the circuit shown in figure switch S is closed at time t=0 At what time current through 3Omega resistance and 1H inductor are equal?

The value of current i_(1) in the given circuit is

When the switch S, in the circuit shown, is closed, then the value of current I will be :