Statement 1: In a series LCR circuit at resonance condition power consumed by ciccuit is maximum.
Statement 2 : At resonance condition, the effective resistance of circuit is maximum.

Options

A. Statement 1 is true, statement 2 is true, Statement 2 is the correct explanation for statement 1.
B. Statemet 1 is True, Statement 2 is true , Statement 2 is NOT the correct explanation for Statement 1
C. Statement 1 is True, Statement 2 is False.
D. Statement 1 is False, Statement 2 is true

Explanation

To analyze the given statements, we will evaluate each one separately.

### Step-by-Step Solution:

1. **Understanding Statement 1**:
- The first statement claims that in a series LCR circuit at resonance condition, the power consumed by the circuit is maximum.
- At resonance, the inductive reactance (XL) equals the capacitive reactance (XC). Therefore, the circuit behaves purely resistively, and the power factor (cos φ) becomes 1.
- The formula for power consumed in an AC circuit is given by:
\[ P = I V \cos \phi \]
- Since cos φ = 1 at resonance, the power consumed (P) is maximized.
- **Conclusion**: Statement 1 is correct.

2. **Understanding Statement 2**:
- The second statement claims that at resonance condition, the effective resistance of the circuit is maximum.
- The impedance (Z) of the circuit is given by:
\[ Z = \sqrt{R^2 + (X_L - X_C)^2} \]
- At resonance, \(X_L = X_C\), which means:
\[ Z = \sqrt{R^2 + 0^2} = R \]
- Thus, the impedance at resonance is equal to the resistance (R), not maximum. The effective resistance does not increase; it remains equal to R.
- **Conclusion**: Statement 2 is incorrect.

3. **Final Evaluation**:
- Since Statement 1 is true and Statement 2 is false, the correct answer is option number three, which states that Statement 1 is true and Statement 2 is false.

### Summary of the Solution:
- Statement 1: True (Power is maximum at resonance).
- Statement 2: False (Effective resistance is equal to resistance, not maximum).
- Correct answer: Option 3.