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A positive charged particle of mass m an...

A positive charged particle of mass m and charge q is projected with velocity v as shown in the figure. If radius of curvature of charged particle in magnetic field is `R(2dltRlt3d),` then time lapse by charged particle in magnetic field regions is :

A

`(2m)/(qB) sin^(-1)((dqB)/(mv))`

B

`(2m)/(qB) sin^(-1)((mv)/(dqB))`

C

`(m)/(qB) sin^(-1)((dqB)/(mv))`

D

`(m)/(qB) sin^(-1)((mv)/(dqB))`

Text Solution

Verified by Experts

The correct Answer is:
C
`R=(mv)/(qB), sin theta=d/R=(dqB)/(mv)`
`t=(2 pi m)/(qB) (theta)/(qB) theta=(m)/(qB) sin^(_1) [(dqB)/(mv)]`
.
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