In the previous problem, what will be force with which system moves? `(Use (sqrt2) =1.4)`

Options

A. `3.05N`
B. `4.0 N`
C. `0.5 N`
D. `1.0 N`

Answer

To solve the problem of determining the force with which the system moves, we will follow these steps:

### Step 1: Identify the forces acting on the system
We have two forces acting on the system:
- \( F_1 = 4 \, \text{N} \) acting in the positive x-direction.
- \( F_2 = 3.5 \, \text{N} \) acting in the negative z-direction.

### Step 2: Determine the net force acting on the system
To find the net force, we need to consider the forces acting in the same direction. Since \( F_1 \) and \( F_2 \) are acting in different directions (x and z), we only need to consider \( F_1 \) for the x-direction.

The net force \( F_{\text{net}} \) in the x-direction can be calculated as:
\[ F_{\text{net}} = F_1 - F_2 \]

### Step 3: Substitute the values
Substituting the values of the forces into the equation:
\[ F_{\text{net}} = 4 \, \text{N} - 3.5 \, \text{N} \]

### Step 4: Calculate the net force
Now, perform the subtraction:
\[ F_{\text{net}} = 0.5 \, \text{N} \]

### Step 5: Determine the direction of the net force
Since \( F_1 \) is greater than \( F_2 \) and acts in the positive x-direction, the net force will also be in the positive x-direction.

### Final Answer
The force with which the system moves is:
\[ \text{Force} = 0.5 \, \text{N} \quad \text{(in the positive x-direction)} \]

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