The faintest sound the human ear can detect at a frequency of 1000 Hz correspond to an intensity of about `1.00xx10^-12(W)/(m^2)`, which is called threshold of hearing. The loudest sounds the ear can tolerate at this frequency correspond to an intensity of about `1.00(W)/(m^2)`, the threshold of pain. Detemine the pressure amplitude and displacement amplitude associated with these two limits. Take speed of sound`=342(m)/(s)` and density of air`=1.20(kg)/(m^3)`

Explanation

To solve the problem, we need to calculate the pressure amplitude and displacement amplitude for both the threshold of hearing and the threshold of pain using the given intensities, speed of sound, and density of air.

### Given Data:
- Frequency (f) = 1000 Hz
- Threshold of Hearing Intensity (I1) = \(1.00 \times 10^{-12} \, \text{W/m}^2\)
- Threshold of Pain Intensity (I2) = \(1.00 \, \text{W/m}^2\)
- Speed of Sound (v) = 342 m/s
- Density of Air (ρ) = 1.20 kg/m³
...