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Two sources A and B are sounding notes o...

Two sources A and B are sounding notes of frequency 680 Hz. A listener moves from A to B with a constant velocity u. If the speed of sound is 340 m/s, What must be the value of u so that he hears 10 beats per second?

A

`2.0(m)/(s)`

B

`2.5(m)/(s)`

C

`30(m)/(s)`

D

`3.5(m)/(s)`

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The correct Answer is:
To solve the problem, we need to find the value of the listener's velocity \( u \) such that he hears 10 beats per second when moving from source A to source B, both emitting sound at a frequency of 680 Hz. The speed of sound in air is given as 340 m/s. ### Step-by-Step Solution: 1. **Identify the Frequencies:** - Both sources A and B emit a frequency \( f_0 = 680 \, \text{Hz} \). 2. **Determine the Apparent Frequencies:** - When the listener moves towards source B, the apparent frequency \( f_B \) heard from source B is given by the formula: \[ f_B = f_0 \left( \frac{v + u}{v} \right) \] where \( v \) is the speed of sound (340 m/s) and \( u \) is the listener's speed. - When the listener moves away from source A, the apparent frequency \( f_A \) heard from source A is given by: \[ f_A = f_0 \left( \frac{v - u}{v} \right) \] 3. **Substituting Values:** - Substitute \( f_0 = 680 \, \text{Hz} \) and \( v = 340 \, \text{m/s} \) into the equations: \[ f_B = 680 \left( \frac{340 + u}{340} \right) = 680 \left( 1 + \frac{u}{340} \right) \] \[ f_A = 680 \left( \frac{340 - u}{340} \right) = 680 \left( 1 - \frac{u}{340} \right) \] 4. **Calculate the Beat Frequency:** - The beat frequency \( \Delta f \) is given by: \[ \Delta f = f_B - f_A \] - Substitute the expressions for \( f_B \) and \( f_A \): \[ \Delta f = 680 \left( 1 + \frac{u}{340} \right) - 680 \left( 1 - \frac{u}{340} \right) \] - Simplifying this gives: \[ \Delta f = 680 \left( \frac{u}{340} + \frac{u}{340} \right) = 680 \left( \frac{2u}{340} \right) = 4u \] 5. **Set the Beat Frequency to 10 Hz:** - We know from the problem that the beat frequency is 10 Hz: \[ 4u = 10 \] 6. **Solve for \( u \):** - Rearranging gives: \[ u = \frac{10}{4} = 2.5 \, \text{m/s} \] ### Final Answer: The value of \( u \) must be \( 2.5 \, \text{m/s} \). ---

To solve the problem, we need to find the value of the listener's velocity \( u \) such that he hears 10 beats per second when moving from source A to source B, both emitting sound at a frequency of 680 Hz. The speed of sound in air is given as 340 m/s. ### Step-by-Step Solution: 1. **Identify the Frequencies:** - Both sources A and B emit a frequency \( f_0 = 680 \, \text{Hz} \). 2. **Determine the Apparent Frequencies:** ...
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