Two trains A and B simultaneously start moving along parallel tracks from a station along same direction. A starts with constant acceleration `2(m)/(s^2)` from rest, while B with the same acceleration but with initial velocity of 40 m/s. Twenty seconds after the start, passenger of A hears whistle of B. If frequency of whistle is 1194 Hz and velocity of sound in air is 322 m/s, calculate frequency observed by the passenger.

Explanation

To solve the problem, we need to follow these steps:

### Step 1: Calculate the velocity of Train A after 20 seconds
Train A starts from rest with a constant acceleration of \(2 \, \text{m/s}^2\). The formula for the final velocity \(v\) after time \(t\) is given by:

\[ v = u + at \]
...