A sound differs by 6 dB from a sound of intensity equal to `10(nW)/(cm^2)`. Find the absolute value of intensity of the sound.

Explanation

To solve the problem, we need to find the absolute value of the intensity of a sound that differs by 6 dB from a sound of intensity \( I_1 = 10 \, \text{nW/cm}^2 \).

### Step-by-step Solution:

1. **Understand the Decibel Formula**:
The difference in intensity in decibels (dB) is given by the formula:
\[
D = 10 \log_{10} \left( \frac{I_2}{I_1} \right)
...