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An observer moves towards a stationary source of sound with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency?

A

`5%`

B

`20%`

C

`0%`

D

`0.5%`

Text Solution

Verified by Experts

The correct Answer is:
B
`f=f_0((v_S+v_0)/(v_S))`
`=f_0[(v+(v)/(5))/(v)]`
`=(6)/(5)f_0`
Hence, percentage increase is
`[((6)/(5)f_0-f_0)/(f_0)]xx100=20%`
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