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A piece of ice of mass of 100g and at te...

A piece of ice of mass of `100g` and at temperature `0^(@)C` is put in `200g` of water of `25^(@)C` .How much ice will melt as the temperature of the water reaches `0^(@)C`? The specific heat capacity of water`= 4200 J kg ^(-1)K^(-1)` and the specific latent heat of ice `= 3.4 xx 10^(5)J kg^(-1)`

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To solve the problem, we need to determine how much ice will melt when a piece of ice at 0°C is placed in water at 25°C. We will follow these steps: ### Step 1: Calculate the heat lost by the water as it cools from 25°C to 0°C. The formula for calculating the heat lost (Q) by the water is: \[ Q = m_w \cdot C_w \cdot \Delta T ...
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A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

A piece of ice of mass 100 g and at temperature 0^@ C is put in 200 g of water of 25^@ C . How much ice will melt as the temperature of the water reaches 0^@ C ? (specific heat capacity of water =4200 J kg^(-1) K^(-1) and latent heat of fusion of ice = 3.4 xx 10^(5) J Kg^(-1) ).

A piece of ice of mass 40 g is added to 200 g of water at 50^@ C. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water = 4200 J kg^(-1) K^(-1) and specific latent heat of fusion of ice = 336 xx 10^3" J "kg^(-1) .

How much heat energy is released when 5.0 g of water at 20^@ C changes into ice at 0^@ C ? Take specific heat capacity of water = 4.2 J g^(-1) K^(-1) , specific latent heat of fusion of ice = 336 J g^(-1) .

How much boiling water at 100^@ C is needed to melt 2 kg of ice so that the mixture, which is all water, is at 0^@ C ? Given : specific heat capacity of water = 4.2 J g^(-1) K^(-1) , specific latent heat of ice = 336 J g^(-1) .

How much heat energy is released when 5 g of water at 20^(@)C changes to ice at 0^(@)C ? [Specific heat capacity of water = 4.2Jg^(-1)""^(@)C^(-1) Specific latent heat of fusion of ice = 336Jg^(-1) ]

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200 g of water at 50.5^@C is cooled down to 10^@C by adding m g of ice cubes at 0^@C in it. Find m. Take, specific heat capacity of water = 4.2Jg^(-1)""^@C^(-1) and specific latent heat of ice = 336Jg^(-1)

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The temperature of 300 g of water at 40^@ C is lowered to 0^@ C by adding ice to it. Find the mass of ice added if specific heat capacity of water is 4.2 J g^(-1) K^(-1) and specific latent heat of ice is 336 J g^(-1)