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How should 1 kg of water at 5^@C be divi...

How should 1 kg of water at `5^@C` be divided into two parts so that if one part turned into ice at `0^@C`, it would release enough heat to vapourize the other part? Latent heat of steam`=540 cal//g` and latent heat of ice `=80 cal//g`.

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To solve the problem, we need to determine how to divide 1 kg of water at 5°C into two parts: one part will be converted into ice at 0°C, and the other part will be vaporized into steam. We will use the principles of calorimetry and the latent heats provided. ### Step-by-step Solution: 1. **Define Variables**: Let \( x \) be the mass of water (in grams) that will be converted into ice. Therefore, the mass of water that will be vaporized is \( 1000 - x \) grams. 2. **Calculate Heat Released by Ice Formation**: ...
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