In a calorimeter (water equivalent`=40g`) are 200g of water and 50 g of ice all at `0^@C`. 30 g of water at `90^@`C is poured into it. What will be the final condition of the system?

Explanation

To solve the problem, we need to analyze the heat exchange in the system consisting of water, ice, and the calorimeter. We will use the principle of conservation of energy, which states that the heat lost by the warmer water will be equal to the heat gained by the ice and the calorimeter.

### Step 1: Identify the components and their initial conditions
- Water in the calorimeter: 200 g at 0°C
- Ice: 50 g at 0°C
- Water poured in: 30 g at 90°C
- Water equivalent of the calorimeter: 40 g

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