`1 kg` ice at `-20^(@)C` is mixed with `1 kg` steam at `200^(@)C`. The equilibrium temperature and mixture content is

Explanation

To solve the problem of finding the equilibrium temperature and mixture content when mixing `1 kg` of ice at `-20°C` with `1 kg` of steam at `200°C`, we can break it down into several steps:

### Step 1: Calculate the heat required to convert ice at `-20°C` to water at `0°C`.

1. **Calculate the heat required to raise the temperature of ice from `-20°C` to `0°C`:**
- The specific heat capacity of ice is approximately `0.5 kcal/kg°C`.
- The formula for heat (Q) is given by:
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