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Two bodies of equal mass m are heated at...

Two bodies of equal mass m are heated at a uniform rate under identical conditions . Their change in temperature are shown graphically in figure .
(i) what are their melting points ?
(ii) what is the ratio of their latent heats?
(iii) what is the ratio of their specific heats?

Text Solution

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The melting points liquids I and II are `60^@` C and `40^@`C, respectively. Let R be the rate of supply of heat. We note from the graph that liquid I is heated through `60^@`C in 2 units of time and that liquid II is heated through `40^@`C in 4 units of time.
`2R=mxxc_1xx60` and `4R=mxxc_2xx40`
Hence, `(c_1)/(c_2)=(1)/(3)`
We note further that the temperature of I remains constant for 4 units of time and that of II for 2 units of time.
`4R=mL_1` and `2R=mL_2implies(L_1)/(L_2)=2`
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