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A refrigerator door is 150 cm high, 80 c...

A refrigerator door is 150 cm high, 80 cm wide, and 6 cm thick. If the coefficient of conductivity is 0.0005 `cal//cm s^@C` and the inner and outer surfaces are at `0^@C` and `30^@C`, respectively, what is the heat loss per minute through the door, in calories?

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To solve the problem of calculating the heat loss per minute through the refrigerator door, we will follow these steps: ### Step 1: Identify the given values - Height of the door (h) = 150 cm - Width of the door (w) = 80 cm - Thickness of the door (T) = 6 cm - Coefficient of conductivity (k) = 0.0005 cal/(cm·s·°C) - Temperature difference (ΔT) = 30°C - 0°C = 30°C ...
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